From ab6a895f4f8914939d302b3a6cb28305b6b86dcd Mon Sep 17 00:00:00 2001 From: Sun Yimin Date: Mon, 25 Sep 2023 21:27:15 +0800 Subject: [PATCH] =?UTF-8?q?Updated=20SM3=E4=B8=AD=E7=9A=84FF2=E5=92=8CGG2?= =?UTF-8?q?=E5=87=BD=E6=95=B0=20(markdown)?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- SM3中的FF2和GG2函数.md | 4 ++++ 1 file changed, 4 insertions(+) diff --git a/SM3中的FF2和GG2函数.md b/SM3中的FF2和GG2函数.md index d65cd8c..3312ef7 100644 --- a/SM3中的FF2和GG2函数.md +++ b/SM3中的FF2和GG2函数.md @@ -55,6 +55,10 @@ $(X \land Y) \bigoplus (X \land Z) $ = $X \land ((Y \land \lnot Z) \lor (\lnot Y \land Z))$ = $(X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)$ +$(X \land Y) \bigoplus (X \land Z) \bigoplus (Y \land Z)$ += $(\lnot((X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)) \land (Y \land Z)) \lor (((X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)) \land (\lnot Y \lor \lnot Z))$ + + $\lnot((X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)) \land (Y \land Z)$ = $\lnot(X \land Y \land \lnot Z) \land \lnot(X \land Z \land \lnot Y) \land (Y \land Z)$ = $(\lnot X \lor \lnot Y \lor Z) \land (\lnot X \lor \lnot Z \lor Y) \land (Y \land Z)$