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Updated SM4 with AESENCLAST (markdown)
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@ -13,7 +13,7 @@ A2(x) = M2*x + C2
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The combinations of (M1, C1, M2, C2) or (A1, A2) are not unique.
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Two known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2).
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Known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2) and [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661). In [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661), we found 8 groups of (M1, C1, M2, C2).
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My question is how to generate all (M1, C1, M2, C2)?
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