From a62e735b724eed976fb2f2a7861e6771158049bd Mon Sep 17 00:00:00 2001 From: Sun Yimin Date: Wed, 27 Oct 2021 16:36:53 +0800 Subject: [PATCH] Updated SM4 with AESENCLAST (markdown) --- SM4-with-AESENCLAST.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/SM4-with-AESENCLAST.md b/SM4-with-AESENCLAST.md index 54c1117..a28d5d4 100644 --- a/SM4-with-AESENCLAST.md +++ b/SM4-with-AESENCLAST.md @@ -13,7 +13,7 @@ A2(x) = M2*x + C2 The combinations of (M1, C1, M2, C2) or (A1, A2) are not unique. -Two known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2). +Known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2) and [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661). In [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661), we found 8 groups of (M1, C1, M2, C2). My question is how to generate all (M1, C1, M2, C2)?