Updated SM3中的FF2和GG2函数 (markdown)

Sun Yimin 2023-09-26 08:05:44 +08:00
parent ab6a895f4f
commit 7e24148498

@ -72,3 +72,6 @@ $(X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y) \lor (Y \land Z)$
= $(X \land Y \land \lnot Z) \lor (X \land Y \land Z) \lor (X \land Z \land \lnot Y) \lor (X \land Y \land Z) \lor (Y \land Z)$
= $(X \land Y) \lor (X \land Z) \lor (Y \land Z)$
相关知识:
* $A \bigoplus B = (\lnot A \land B) \lor (A \land \lnot B) $
* [布尔代数运算律](https://baike.baidu.com/item/%E5%B8%83%E5%B0%94%E4%BB%A3%E6%95%B0%E8%BF%90%E7%AE%97%E5%BE%8B/22804079)