Updated SM3中的FF2和GG2函数 (markdown)

Sun Yimin 2023-09-25 17:32:32 +08:00
parent eeec48f1ba
commit 73b06c2c92

@ -57,10 +57,10 @@ $(X \land Y) \bigoplus (X \land Z) $
$\lnot((X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y))$
= $\lnot(X \land Y \land \lnot Z) \land \lnot(X \land Z \land \lnot Y)$
= $(\lnot X \lor \lnot Y \lor Z) \lor (\lnot X \lor \lnot Z \lor Y)$
= $(\lnot X \lor \lnot Y \lor Z) \land (\lnot X \lor \lnot Z \lor Y)$
$((X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)) \land (\lnot Y \lor \lnot Z)$
= $(X \land Y \land \lnot Z) \lor (X \land Z \land \lnot Y)$
$((\lnot X \lor \lnot Y \lor Z) \lor (\lnot X \lor \lnot Z \lor Y)) \land (Y \land Z)$
$((\lnot X \lor \lnot Y \lor Z) \land (\lnot X \lor \lnot Z \lor Y)) \land (Y \land Z)$
= $(\lnot X \land Y \land Z)$