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Updated SM4 with AESENCLAST (markdown)

Sun Yimin 2022-03-04 14:17:57 +08:00
parent fd0ff5388c
commit 247e0fa63c
1 changed files with 1 additions and 3 deletions
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SM4-with-AESENCLAST.md

@ -13,9 +13,7 @@ A2(x) = M2*x + C2
The combinations of (M1, C1, M2, C2) or (A1, A2) are not unique. The combinations of (M1, C1, M2, C2) or (A1, A2) are not unique.
Known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2) and [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661). In [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661), we found 8 groups of (M1, C1, M2, C2). Known (M1, C1, M2, C2), please reference [sm4 with AESENCLAST](https://gist.github.com/emmansun/ae4677d71c75ff8407d5f5b3a884f5d2) and [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661). In [AES 和 SM4 S盒複合域實現方法python code](https://gist.github.com/emmansun/9f8d449072f6048538add79bd146b661), we found 8 groups of (M1, C1, M2, C2). 其实按[A very compact Rijndael S-box](https://calhoun.nps.edu/bitstream/handle/10945/791/NPS-MA-04-001.pdf?sequence=1&isAllowed=y)，这八组对应**E All Possible Bases**的八组正规基：1 4 19 22 37 40 55 58，另外还有73 76 91 94 109 112 127 130八组正规基，其它都是混合基或者多项式基，共432组，它们都假设trace is unity。
My question is how to generate all (M1, C1, M2, C2)?
``` ```
{(M1, C1, M2, C2) | SM4-S(x) = A2(AES-S(A1(x)), A1(x) = M1*x + C1, A2(x) = M2*x + C2} {(M1, C1, M2, C2) | SM4-S(x) = A2(AES-S(A1(x)), A1(x) = M1*x + C1, A2(x) = M2*x + C2}