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Updated MFMM (markdown)
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MFMM.md
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MFMM.md
@ -2,9 +2,6 @@ MFMM=[Montgomery Friendly modules Montgomery Multiplication](https://eprint.iacr
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首先NIST P256 / SM2 256 的素数P都是Montgomery Friendly modules。
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首先NIST P256 / SM2 256 的素数P都是Montgomery Friendly modules。
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SM2 256 的素数P=0xfffffffeffffffffffffffffffffffffffffffff00000000ffffffffffffffff,也可以表示为
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$P = 2^{256}-(2^{32} \ast 2^{192} + 0 \ast 2^{128} + (2^{32} - 1) \ast 2^{64} + 1)$
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输入:
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输入:
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X, Y都是Montgomery数值表示
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X, Y都是Montgomery数值表示
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@ -285,3 +282,22 @@ acc0, acc1, acc2, acc3, acc4, acc5是64位寄存器
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BenchmarkMoreThan32_P256SM2-2 4550 263296 ns/op
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BenchmarkMoreThan32_P256SM2-2 4550 263296 ns/op
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PASS
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PASS
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ok github.com/emmansun/gmsm/sm2 4.753s
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ok github.com/emmansun/gmsm/sm2 4.753s
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### 续
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SM2 256 的素数P=0xfffffffeffffffffffffffffffffffffffffffff00000000ffffffffffffffff,也可以表示为
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$P = 2^{256}-(2^{32} \ast 2^{192} + 0 \ast 2^{128} + (2^{32} - 1) \ast 2^{64} + 1)$
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这样,可以通过移位和加减操作来实现模约减。
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假设:
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$T=t_7 \ast 2^{448} + t_6 \ast 2^{384} + t_5 \ast 2^{320} + t_4 \ast 2^{256} + t_3 \ast 2^{192} + t_2 \ast 2^{128} + t_1 \ast 2^{64} + t_0 $
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则共四次约减,第一次约减为:
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$T_1=t_0$
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$T_2=T_1 \ast P=t_0 \ast P= t_0 \ast (2^{256}-(2^{32} \ast 2^{192} + 0 \ast 2^{128} + (2^{32} - 1) \ast 2^{64} + 1))$
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$T_2=t_0 \ast 2^{256} - t_0 \ast 2^{32} \ast 2^{192} - t_0 \ast (2^{32} - 1) \ast 2^{64} - t_0$
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$T_3=T + T_2=t_7 \ast 2^{448} + t_6 \ast 2^{384} + t_5 \ast 2^{320} + t_4 \ast 2^{256} + t_3 \ast 2^{192} + t_2 \ast 2^{128} + t_1 \ast 2^{64} + t_0 \ast 2^{256} - t_0 \ast 2^{32} \ast 2^{192} - t_0 \ast (2^{32} - 1) \ast 2^{64} - t_0 $
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$T_3=t_7 \ast 2^{448} + t_6 \ast 2^{384} + t_5 \ast 2^{320} + (t_4+t_0) \ast 2^{256}+(t_3 - t_0 \ast 2^{32}) \ast 2^{192} + t_2 \ast 2^{128} + (t_1 + t_0 - t_0 \ast 2^{32}) \ast 2^{64} $
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