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internal/bigmod: sync sdk #200
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@ -318,14 +318,48 @@ type Modulus struct {
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// rr returns R*R with R = 2^(_W * n) and n = len(m.nat.limbs).
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func rr(m *Modulus) *Nat {
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rr := NewNat().ExpandFor(m)
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// R*R is 2^(2 * _W * n). We can safely get 2^(_W * (n - 1)) by setting the
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// most significant limb to 1. We then get to R*R by shifting left by _W
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// n + 1 times.
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n := len(rr.limbs)
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rr.limbs[n-1] = 1
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for i := n - 1; i < 2*n; i++ {
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rr.shiftIn(0, m) // x = x * 2^_W mod m
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n := uint(len(rr.limbs))
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mLen := uint(m.BitLen())
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logR := _W * n
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// We start by computing R = 2^(_W * n) mod m. We can get pretty close, to
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// 2^⌊log₂m⌋, by setting the highest bit we can without having to reduce.
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rr.limbs[n-1] = 1 << ((mLen - 1) % _W)
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// Then we double until we reach 2^(_W * n).
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for i := mLen - 1; i < logR; i++ {
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rr.Add(rr, m)
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}
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// Next we need to get from R to 2^(_W * n) R mod m (aka from one to R in
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// the Montgomery domain, meaning we can use Montgomery multiplication now).
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// We could do that by doubling _W * n times, or with a square-and-double
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// chain log2(_W * n) long. Turns out the fastest thing is to start out with
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// doublings, and switch to square-and-double once the exponent is large
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// enough to justify the cost of the multiplications.
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// The threshold is selected experimentally as a linear function of n.
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threshold := n / 4
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// We calculate how many of the most-significant bits of the exponent we can
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// compute before crossing the threshold, and we do it with doublings.
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i := bits.UintSize
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for logR>>i <= threshold {
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i--
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}
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for k := uint(0); k < logR>>i; k++ {
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rr.Add(rr, m)
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}
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// Then we process the remaining bits of the exponent with a
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// square-and-double chain.
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for i > 0 {
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rr.montgomeryMul(rr, rr, m)
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i--
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if logR>>i&1 != 0 {
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rr.Add(rr, m)
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}
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}
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return rr
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}
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@ -775,26 +809,21 @@ func (out *Nat) Exp(x *Nat, e []byte, m *Modulus) *Nat {
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return out.montgomeryReduction(m)
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}
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// ExpShort calculates out = x^e mod m.
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// ExpShortVarTime calculates out = x^e mod m.
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//
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// The output will be resized to the size of m and overwritten. x must already
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// be reduced modulo m. This leaks the exact bit size of the exponent.
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func (out *Nat) ExpShort(x *Nat, e uint, m *Modulus) *Nat {
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xR := NewNat().Set(x).montgomeryRepresentation(m)
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out.resetFor(m)
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out.limbs[0] = 1
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out.montgomeryRepresentation(m)
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// be reduced modulo m. This leaks the exponent through timing side-channels.
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func (out *Nat) ExpShortVarTime(x *Nat, e uint, m *Modulus) *Nat {
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// For short exponents, precomputing a table and using a window like in Exp
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// doesn't pay off. Instead, we do a simple constant-time conditional
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// square-and-multiply chain, skipping the initial run of zeroes.
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tmp := NewNat().ExpandFor(m)
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for i := bits.UintSize - bitLen(e); i < bits.UintSize; i++ {
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// doesn't pay off. Instead, we do a simple conditional square-and-multiply
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// chain, skipping the initial run of zeroes.
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xR := NewNat().Set(x).montgomeryRepresentation(m)
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out.Set(xR)
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for i := bits.UintSize - bitLen(e) + 1; i < bits.UintSize; i++ {
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out.montgomeryMul(out, out, m)
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k := (e >> (bits.UintSize - i - 1)) & 1
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tmp.montgomeryMul(out, xR, m)
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out.assign(ctEq(k, 1), tmp)
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if k := (e >> (bits.UintSize - i - 1)) & 1; k != 0 {
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out.montgomeryMul(out, xR, m)
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}
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}
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return out.montgomeryReduction(m)
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}
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@ -303,7 +303,7 @@ func TestExpShort(t *testing.T) {
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m := modulusFromBytes([]byte{13})
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x := &Nat{[]uint{3}}
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out := &Nat{[]uint{0}}
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out.ExpShort(x, 12, m)
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out.ExpShortVarTime(x, 12, m)
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expected := &Nat{[]uint{1}}
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if out.Equal(expected) != 1 {
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t.Errorf("%+v != %+v", out, expected)
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@ -383,6 +383,13 @@ func makeBenchmarkExponent() []byte {
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return e
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}
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func BenchmarkRR256(b *testing.B) {
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b.ResetTimer()
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for i := 0; i < b.N; i++ {
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makeBenchmarkModulus(4)
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}
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}
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func BenchmarkModAdd(b *testing.B) {
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x := makeBenchmarkValue(32)
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y := makeBenchmarkValue(32)
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