120 lines
3.6 KiB
Go
120 lines
3.6 KiB
Go
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// Package ltp 长期岁差的黄极与赤道极向量(J2000 平赤道坐标,±20 万年有效)。
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package ltp
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import "math"
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const (
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as2r = 4.848136811095359935899141e-6
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d2pi = 6.283185307179586476925287
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eps0 = 84381.406 * as2r
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)
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// Vector3 三维向量 / a 3-vector.
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type Vector3 [3]float64
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// EclipticPole 历元平黄道极 / mean ecliptic pole of epoch, epj in Julian years.
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func EclipticPole(epj float64) Vector3 {
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pqPol := [2][4]float64{
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{+5851.607687, -0.1189000, -0.00028913, +0.000000101},
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{-1600.886300, +1.1689818, -0.00000020, -0.000000437},
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}
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pqPer := [8][5]float64{
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{708.15, -5486.751211, -684.661560, 667.666730, -5523.863691},
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{2309.00, -17.127623, 2446.283880, -2354.886252, -549.747450},
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{1620.00, -617.517403, 399.671049, -428.152441, -310.998056},
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{492.20, 413.442940, -356.652376, 376.202861, 421.535876},
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{1183.00, 78.614193, -186.387003, 184.778874, -36.776172},
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{622.00, -180.732815, -316.800070, 335.321713, -145.278396},
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{882.00, -87.676083, 198.296071, -185.138669, -34.744450},
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{547.00, 46.140315, 101.135679, -120.972830, 22.885731},
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}
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t := (epj - 2000.0) / 100.0
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p, q := 0.0, 0.0
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for i := 0; i < 8; i++ {
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w := d2pi * t
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a := w / pqPer[i][0]
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s := math.Sin(a)
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c := math.Cos(a)
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p += c*pqPer[i][1] + s*pqPer[i][3]
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q += c*pqPer[i][2] + s*pqPer[i][4]
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}
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w := 1.0
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for i := 0; i < 4; i++ {
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p += pqPol[0][i] * w
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q += pqPol[1][i] * w
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w *= t
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}
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p *= as2r
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q *= as2r
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z := math.Sqrt(math.Max(1.0-p*p-q*q, 0.0))
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s := math.Sin(eps0)
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c := math.Cos(eps0)
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return Vector3{p, -q*c - z*s, -q*s + z*c}
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}
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// EquatorPole 历元平赤道极 / mean equator pole of epoch, epj in Julian years.
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func EquatorPole(epj float64) Vector3 {
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xyPol := [2][4]float64{
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{+5453.282155, +0.4252841, -0.00037173, -0.000000152},
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{-73750.930350, -0.7675452, -0.00018725, +0.000000231},
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}
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xyPer := [14][5]float64{
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{256.75, -819.940624, 75004.344875, 81491.287984, 1558.515853},
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{708.15, -8444.676815, 624.033993, 787.163481, 7774.939698},
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{274.20, 2600.009459, 1251.136893, 1251.296102, -2219.534038},
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{241.45, 2755.175630, -1102.212834, -1257.950837, -2523.969396},
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{2309.00, -167.659835, -2660.664980, -2966.799730, 247.850422},
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{492.20, 871.855056, 699.291817, 639.744522, -846.485643},
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{396.10, 44.769698, 153.167220, 131.600209, -1393.124055},
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{288.90, -512.313065, -950.865637, -445.040117, 368.526116},
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{231.10, -819.415595, 499.754645, 584.522874, 749.045012},
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{1610.00, -538.071099, -145.188210, -89.756563, 444.704518},
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{620.00, -189.793622, 558.116553, 524.429630, 235.934465},
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{157.87, -402.922932, -23.923029, -13.549067, 374.049623},
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{220.30, 179.516345, -165.405086, -210.157124, -171.330180},
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{1200.00, -9.814756, 9.344131, -44.919798, -22.899655},
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}
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t := (epj - 2000.0) / 100.0
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x, y := 0.0, 0.0
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for i := 0; i < 14; i++ {
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w := d2pi * t
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a := w / xyPer[i][0]
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s := math.Sin(a)
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c := math.Cos(a)
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x += c*xyPer[i][1] + s*xyPer[i][3]
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y += c*xyPer[i][2] + s*xyPer[i][4]
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}
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w := 1.0
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for i := 0; i < 4; i++ {
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x += xyPol[0][i] * w
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y += xyPol[1][i] * w
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w *= t
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}
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x *= as2r
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y *= as2r
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w = x*x + y*y
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z := 0.0
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if w < 1.0 {
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z = math.Sqrt(1.0 - w)
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}
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return Vector3{x, y, z}
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}
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// Cross 叉乘 / cross product.
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func Cross(a, b Vector3) Vector3 {
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return Vector3{
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a[1]*b[2] - a[2]*b[1],
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a[2]*b[0] - a[0]*b[2],
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a[0]*b[1] - a[1]*b[0],
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}
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}
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// Normalize 单位向量与原模长,零向量返回零 / unit vector and norm; zero stays zero.
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func Normalize(p Vector3) (Vector3, float64) {
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w := math.Sqrt(p[0]*p[0] + p[1]*p[1] + p[2]*p[2])
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if w == 0.0 {
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return Vector3{0, 0, 0}, 0
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}
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return Vector3{p[0] / w, p[1] / w, p[2] / w}, w
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}
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